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Q2 Sin[ 2cos-1{cot(2tan-1 x)} ]= 0...... solve for positive value of x...
a) x=1,√2-1,√2+1
b) x=1,12,13
c) x=1,√3-1,√3+1
d) x=√2+1,√3-1

13 Answers

1
Aditya ·

ques is not clear..!...r the brackets correct?

1
Lonely 1 ·

IT IS A SIMPLE 1
I AM GETTING (A)

WHAT I USED THE FACT IS A TRIANGLE
MAKE A TRIANGLE U WILL GET THE ANSWER

11
Subash ·

now edited

62
Lokesh Verma ·

yes that is the best way to do it lonely :)

11
Subash ·

but how to find cot(2tan-1x)

1
Lonely 1 ·

2 tan-1x=tan-12x/1-x2

11
Subash ·

so from there we get

sin{2cos-1(1-x2/2x)}

then?

please bear with me this might be very silly :(

1
Lonely 1 ·

dude u r smart
put the values if u don't want to solve it fully

and no question is silly
every thing has its own importance

if u wish to solve it fully then as u wish [1]

62
Lokesh Verma ·

sin 2x = 2 sin x cos x :)

62
Lokesh Verma ·

or else

sin 2x = 0 implies that 2x= n pi

11
Subash ·

is this correct?

2cos-1x=cos-1(2x2-1)

11
Mani Pal Singh ·

SUBASH

2cos-1x=cos-1(2x2-1)

ONLY WHEN 0≤x≤1

11
Subash ·

k thanks manipal :)

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