Algebra - "CLASSY" probability

62

Lokesh Verma ·2009-04-09 11:06:28

See the most important thing si that

Î£P(Ek) = 1

hence (n+1).c=1

Thus, P(Ek) = 1/(n+1)

now we have P(0)=1/(n+1)

P(k) = (k+1)/n+1

P(k) is the probability that atmost k students have failed...

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vector ·2009-04-09 11:28:04

edited[1]

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tapanmast Vora ·2009-04-09 11:26:46

Thnx a lot SirJee and RICHA!! [1]

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tapanmast Vora ·2009-04-09 11:24:40

OH got it now!!! finally [2] [1] [1]

Richa edit this un : p(a)=Î£1/n+1(k/n) it shud be p(a)=Î£[(1/(n+1))*(k/n)]

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vector ·2009-04-09 11:21:06

see p(a)=p(a/ek)p(ek) rite....
now p(ek)=c=1/n+1 kkk
n now p(a/ek)=k/n
lyk if it s given 2 students pass
it means p(tht student choosen is passed is 2/n na
so p(passing /k students pssed is k/n)
now summation k=o to n u ll get the ans

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MATRIX ·2009-04-09 11:19:08

?

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vector ·2009-04-09 11:16:37

i m sorry fr mistyping edited

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tapanmast Vora ·2009-04-09 11:15:38

i m stioll confused [2]

can u give the logical statement for ur P(A)

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Mani Pal Singh ·2009-04-09 11:15:37

yeh TMH ka problem hai
A VERY BAD 1 !!!!!!!!!!!!!!!!

i completely ununderstood that

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vector ·2009-04-09 11:12:36

p(a)=Î£(1/n+1)*(k/n)

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vector ·2009-04-09 11:10:43

main bhi yahi bol rahi thi[1]

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tapanmast Vora ·2009-04-09 11:09:52

P(k) = (k+1)/n+1
kaise ??

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vector ·2009-04-09 11:08:28

after c value it slyk
1/n*1/n+1+2/n*1/n+1........n/n*1/n+1

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avni ·2009-04-09 10:30:53

ne1?

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vector ·2009-04-09 11:05:29

n as p(ek)=c

c+c+......c(n+1 times)=(n+1)c=1
after tht i think its easy

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tapanmast Vora ·2009-04-09 11:05:27

hmmm value of C i too got,

Sir is solving it , wait 4 sumtime

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vector ·2009-04-09 11:03:35

i gotthoda thoda lyk the events r exhaustive n mutually exclusive
so p(e0)+p(e1)+...............p(en)=1

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tapanmast Vora ·2009-04-09 11:02:58

Baye's has been BOOING me off-late [2]

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11

rkrish ·2009-04-09 10:55:13

nish. bhaiyya......pls. help !!!

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rkrish ·2009-04-09 10:53:58

me too...even i didnt understand [2][2]

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tapanmast Vora ·2009-04-09 10:52:53

Can sum1 give a mor clarified version, i din eXACTLY get wat gordo said in da abv link

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rkrish ·2009-04-09 10:43:39

http://targetiit.com/iit_jee_forum/posts/mathematics_4452.html
post #13

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tapanmast Vora ·2009-04-09 10:41:39

can u give da link , Richa

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vector ·2009-04-09 10:39:51

dis ve been posted in tiit by manipal

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tapanmast Vora ·2009-04-09 10:37:53

[12] [12] kabka [12]

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