Simple one...

Just a simple question for all...

if x and y are two complex roots of Zn=1

then what is the condition on "n" that Arg(x/y)=pi/2 has a possiblity? (n is an integer!)

20 Answers

62
Lokesh Verma ·

@priyam... well i forgot to say n is an integer!

33
Abhishek Priyam ·

haan... abhi to wahi hai...

62
Lokesh Verma ·

so n=360k .. k>0 an integer

was this your answer?

33
Abhishek Priyam ·

aur sochna padega kya....

62
Lokesh Verma ·

yup.. answer ajeeb hai..
but somtimes ajeeb answers are right...

sign wahi se bana ;)

33
Abhishek Priyam ·

n=360r/29

so we should take r=29k

so n=360k .. k>0 an integer... [5]

ajeeb hai..

app bhi sign... :P

62
Lokesh Verma ·

What is all this photogiri...

chalo now finally post the correct answer to the question :P

33
Abhishek Priyam ·

Ok..

so n is integer...

33
Abhishek Priyam ·

Is it something to do that n is not coming out integer... [12]

13
Двҥїяuρ now in medical c ·

33
Abhishek Priyam ·

n=4r.. r>0 and r is integer...

33
Abhishek Priyam ·

:D

62
Lokesh Verma ·

http://www.mediafire.com/images/icons/ajax-loader-bar.gif

33
Abhishek Priyam ·

hmm..... koi trap me fas gaya kya main... [12]

13
Двҥїяuρ now in medical c ·


yeh kya hai???????

62
Lokesh Verma ·

chalo lets do a still simpler one..

what if the difference is 7 degrees ;)

33
Abhishek Priyam ·

galat hai kya... 290 wala....

33
Abhishek Priyam ·

360.r/n=29

62
Lokesh Verma ·

what if the angle was 29 degrees?

62
Lokesh Verma ·

good work :)

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