solve

2^x= x2+1

i am getting two.... 0 and 1.

ny other???

9 Answers

62
Lokesh Verma ·

Well this was a gr8 question by Abhishek....

I got blown as well...

I thought it was 2 but it is actually 3.. the graph method killed me :D
On carefullly seeing i realised my graph was wrong :(

There is one root between 4 and 5
!!

How do we find out?

I cannot think of a brilliant solution...

But yeah u could try taking derivative.. find where it is zero...
check the signs at these points and +- infinity.

62
Lokesh Verma ·

finding the zeroes will need graphs. That is probably the best way!

Unfortunately, even here, we cant get a exact value of roots!

I am not sure how a better and more correct solution could be found!!!

Ne suggestions?

1
skygirl ·

now..........
how to know when graph method will be correct n when it will betray us this way....??????????

33
Abhishek Priyam ·

ok skygirl two soln u figured 0 and 1 well that was the trick and u did it now at x=1 x2+1 overtook 2x and lim(x→∞) 2x-(x2+1)>0 so 2x overtakes x2+1 so it will definitely cut x2+1 giving a third soln. but will there be two more solns it is tricky (definitely it will have odd no of solns)

In objective question this much info is enough for choosing a option this will never be asked in subjective.

I solved it in test options given were

1
2
3
4

now which option is odd and i knew it will be more than 2 so 3 solns

Further U can check behaviour by putting some values. It is helpful in tests..

1
skygirl ·

well.......
thank you :)

1
voldy ·

Can you prove lim (x→∞) 2x - (x2+1) > 0

I'm not really convinced . expand 2x . That'll give .

1+(xln2) + (xln2)2 ...... -x2 -1 .
= xln2 + x2 ( .693 2 - 1) ....... I mean this is infinity you're dealing with. So , I just don't feel you can state that.

62
Lokesh Verma ·

nothing to prove srinath....

actually exponentials grow faster than polynomials in the long run....

see the derivative...

2xln2 and 2x

as x grows.. the first one far far supersedes the 2nd... it is inevitable that it will go beyond the 2nd

From now on, take it for a fact :)

1
voldy ·

the derivative gives the slope of the tangent , so it means that since 2xln2 increases more , the fn achieves greater values for small increments of x . This is what you mean . Right?
Thank you.

62
Lokesh Verma ·

yes i mean that..

so essentially one is moving very very fast.. and forever... so it will overtake the slower one evenutally :)

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