solve for x

\hspace{-16}$Solve for $\mathbf{x}$\\\\ $\mathbf{x^2-2x+2=\log_{\frac{2}{3}}(x^2+1)+\log_{\frac{2}{3}}(3x)}$

2 Answers

on the RHS is it logA + logB or logA - logB ? where A and B are x^2+1&3x.

1708

man111 singh ·2011-11-21 09:56:07

yes Rishab you are saying Right

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