2305@Sourish: When I say sum of 2 squares....I obviously mean that the 2 no.s are integers.(Otherwise it becomes too easy).
The 2 no.s given by u are not integers.
Cuz it is not necessary for (m3+n3)2 to be divisible by 2.
Represent m6+n6 as a sum of 2 squares other than (m3)2+(n3)2.
Think its easy....give it a try!:P
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4 Answers
1133(\frac{m^{3} + n^{3}}{\sqrt{2}})^{2} + (\frac{m^{3} - n^{3}}{\sqrt{2}})^{2}
23052305Let me get this clarified-If m6+n6=c2+d2 then c and d need to be positive integers.
Himanshu Giria no c&d can be -ve integers too
but c sq. and d sq. will be +ve integers
Upvote·0· Reply ·2013-05-26 04:49:34