71Using Rotation theorem at C and A, We can easily find out the the co ordinates of C
\hspace{-16}$The Complex no. Corrosponding to the point of Intersection of\\\\ Tangents at $\mathbf{(4-\sqrt{5}.i)}$ and $\mathbf{(-\sqrt{5}.i)}$ on the Circle $\mathbf{\mid z-2\mid = 3}$ is
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2 Answers
71
1circle is (x-2)2 + y2 = 9
tangent at point (x1,y1) is T=0
=>the tangents at given points are,
2x+√5y +5=0 & 2x - √5 y -13 = 0
solving we get the point 4-(9√5) i
