1put x=-x in d equation u ll get it as odd by simplification
\int_{-1}^{1}{g'(x)dx} \: =
ANS : 2g(1)
Wer in the Questn is it Given g(x) is an ODD Functn ??? [7]
and widout that HOW CAN g(1) - g(-1) = 2g(1) ???????????????
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6 Answers
21Actually MY BIGGEST doubt is dat wer is it written that the equation : y3 - 3y + x = 0
has any DAMN relation wid f(x) and g(x) .........
21And even if so then Y divide it into two grps, one named f(x) and other as g(x)
wen they represnt the same thing !!!!