2008 EK aur asamanjhas ......

\int_{-1}^{1}{g'(x)dx} \: =

ANS : 2g(1)

Wer in the Questn is it Given g(x) is an ODD Functn ??? [7]

and widout that HOW CAN g(1) - g(-1) = 2g(1) ???????????????

6 Answers

put x=-x in d equation u ll get it as odd by simplification

Actually MY BIGGEST doubt is dat wer is it written that the equation : y³ - 3y + x = 0

has any DAMN relation wid f(x) and g(x) .........

And even if so then Y divide it into two grps, one named f(x) and other as g(x)

wen they represnt the same thing !!!!

it simply mean in (-2,2) consider y=g(x)

it only done to make d q complicated nothing else

ye to sarasar na-insafi hain !!!

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