# LMVT Question

if f(x)=loge x and g(x)=x2 and 4<c<5

then

c log (425/516) is equal to

(a) c loge5 - 8

(b) 2(c2 loge4 - 8)

(c) 2(c2 loge5 - 8)

(d) c loge4 - 8

39
Dr.House ·

if f(x)=loge x and g(x)=x2 and c (4,5)

wat is c(4,5) could u please clarify?

1
Rajat Agarwal ·

No one here who can solve this Problem.....................???????????????

1
Rajat Agarwal ·

Plz any bhaiya solve this..... y is no one replying??????????..................

62
Lokesh Verma ·

rajat what is the source of this question...??

I feel something wrong or mistyped..

I dont find any use of c lying betweeen 4 and 5!!!

1
Rajat Agarwal ·

No bhaiya da question is correct.... it is from arihant mathematics..

1
gordo ·

look, first of all, i feel this q. is too ambiguous,

as far as the solution is concerned,

say h(x)=x2log4-16logx

h(x) is diff. and continuous in (4,5)

we have by LMVT,

h(5)-h(4) /5-4 = h'(c) where c is in (4,5)

so,

we have [25log4 - 16log5]-[0] = 2clog4-16/c

or log(425/516) =(2c2log4 -16)/c2

that way im getting

c log(425/516)= 2(c2log4-8)/c

but i thing i can say is, the question shud ask us to make use of these functions, other wise there mite be many many ways of solving this one, which may use many different 'c' s..

cheers!!

1
Rajat Agarwal ·

thanks...... gordo......

1
Ransariya Divyesh ·

Marathi thai gayo bbccffghkkiydf