area problem.....

find the smallest area by y=f(x), when f(x) is a polynomial of least degree satisfying lim(x->0) [1+(f(x)/x^3)]^(1/x)=e,
and the circle x^2+y^2=2 above the x-axis.

13 Answers

62
Lokesh Verma ·

First in this question you need to find f(x) in a general form!

What that means is that take Σakxk for general k and see when this will converge. Now there will be a general form of equations which will satisfy this.

So you need to take the polynomial which will give the least area!

So the first step will be to find the general polynomial.

Then we will work on the next step of finding the area!

1
skygirl ·

sorry:(
i didn get u...
how to find the general form???
ok.........is it from the limits?? but how.. pls tell...

62
Lokesh Verma ·

The general form is not very tough...

first step: find k for which akxk which give the limit as finite!

1
skygirl ·

x4 should give it .....right?

62
Lokesh Verma ·

yes

now what will be the limit if f(x) = constant?

or f(x) = k.x

or f(x) = k.x2

62
Lokesh Verma ·

also when f(x) = x5

or when f(x) = x6

1
skygirl ·

0 ??

11
Shailesh ·

ok now try

f(x) = x4+x5

1
skygirl ·

zero..

62
Lokesh Verma ·

gr8..

so we know that all polynomials of the form

f(x) = x4 + x5{g(x)} where g(x) is a polynomial will satisfy....

1
skygirl ·

haan.......and so the least is x4...
then finding out area from here is rather simple.....
thank you so much........!!!!!!!!!!!! :)

11
Shailesh ·

why not ? x4- x5??

62
Lokesh Verma ·

because we want polynomial of least degree :)

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