1Q1 is not invertible...
itis not one-one onto...
see -9/4<x(x-3)<infi
so range of 3^x(x-3) not =R so not onto
can someone plz tell me how to do these types:
1.
is the function f:R→R 3x(x-3) invertible??
if not change its domain so that it becomes so.
2.let g(x)=x2-4x-5
a) g is one-one on R
b)g is one-one on (-∞,2]
c)g is not one-one on (-∞,4]
d)g is one-one on (-∞,0)
ans is given as b,d for Q2 , my doubt is why not c) also???? (As function's derivative's slope is 0 at x=2)??
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3 Answers
1see one one fn is either increasing or dec..solving u get b,d
1
1what 's wrong with C) the funtcion is not invertible at 2 which is included in the given doman. So whats wrong with the statement