calculus

f(x)= xⁿ sinx cosx
n! sin((npi)/2) cos((npi)/2)
a a² a³

show that dⁿ/dxⁿ[f(x)] at x=0 is 0....

#Mathematics #Calculus

1 Answers

When we have a determinant with one single variable row, then we can differentiate the row alone...

the nth derivative will be n! , nth derivative of sin x and nth derivative of cos x

Now can u give it a shot taking n as 4k or 4k+1 or 4k+2 or 4k+3

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