Critical Points

BITSAT 2015 Answers › Calculus questions › Critical Points

Let f(x) =(x-1)p.(x-2)q where p,q>1. Each critical point of f(x) is a point of extremum when - (Options are given)

I got the critical points as 1 and 2.
I don't know what do I do next. I found the second derivative but I think its of no use.

#Mathematics #Calculus

UP 0 DOWN 0 0 5
Post on FacebookPost anonymously?

5 Answers

aditya chatterjee ·2010-12-07 01:20:52

what are the options?

UP 0 DOWN 0
Post on FacebookPost anonymously?

aditya chatterjee ·2010-12-07 01:36:38

i dont know how u got 1 and 2. i see that f1(x)=0 at 3/2

UP 0 DOWN 0
Post on FacebookPost anonymously?

swordfish ·2010-12-07 02:22:14

aargh!! the question was
(x-1)^p.(x-2)^q
I got an answer anyways.
We had to find the nature of p and q
answer is p and q are even

UP 0 DOWN 0
Post on FacebookPost anonymously?

341

Hari Shankar ·2010-12-07 03:45:45

Read both:

http://www.goiit.com/posts/listByUser/1820/5929.htm

http://www.goiit.com/posts/list/differenciation-an-easy-one-44443.htm

UP 0 DOWN 0
Post on FacebookPost anonymously?

swordfish ·2010-12-07 04:25:23

OMG Prophet Sir, You are from IIT-M?
I am a fan of yours :)
thanks alot. that helped
I found a method by drawing the graph substituting the values of p and q. But that would be tedious.

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

Close [X]

Critical Points

5 Answers

Your Answer

Add Image

Similar Questions