106your answer is correct
in the fuct. f(x) = | Sin x | ...... which points are described as non-diff points......
i 've ans it as
at x=nπ , n ε I.... the grapgh will be non-differential,..... but the ans given in the buk is at only x=0 , the graph is non-differential......
-
UP 0 DOWN 0 0 13
13 Answers
6
wherever the cureve becomes sharp it is discont there!!!
here it becomes discont at x=nπ!!!
thus it becomes the point of discontinuity!!!
1@kalyan it doesn't become discontinuous where curve has sharp points.....it's nt differentiable there..:P
49he meant that only....
just the word got mixed up ;)
hota hai sabke saath! :P
6yeah write i meant the same!!
sorry
kya mujhe iske liye pink milega?? LOL
6bhavna kaun hai akhil...ahem ahem!!!...LOL LOL :P
1i have given answer of some nice questions. but did not get even a single pink post. koi baat nahi chalta hai
