DIFFERENTIATION

VITEEE 2015 Discussion Forum › Calculus questions › DIFFERENTIATION

is this a DONKEY's toil - work Question Or has some more Elegant - Plausible Approach to it ?? [7]

#Mathematics #Calculus

UP 0 DOWN 0 1 11
Post on FacebookPost anonymously?

11 Answers

21

tapanmast Vora ·2009-04-02 23:36:40

koi to try karo....

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

rkrish ·2009-04-02 23:38:52

Did not solve completely.....but....

try putting xy = Î¸
So, (Î¸,y) â‰¡ (8,2)

Convert the entire thing to sin & cos.

I dont it'll help much.

UP 0 DOWN 0
Post on FacebookPost anonymously?

1357

Manish Shankar ·2009-04-02 23:40:52

let it be f(xy)=14

differentiating wrt to y

f'(xy)[(y+xdx/dy]=0

this might help

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

rkrish ·2009-04-02 23:45:18

this is good bhaiyya ......thanx.....

Ans :comes out to be -2

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

rkrish ·2009-04-02 23:49:42

hey.....f '(xy) is a non-zero constant at (4,2)

UP 0 DOWN 0
Post on FacebookPost anonymously?

21

tapanmast Vora ·2009-04-02 23:51:47

so ....

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

vector ·2009-04-02 23:53:19

dy/dx =-y/x then it means ans is -1/2

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

vector ·2009-04-02 23:56:14

temme wer i m wrong

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

rkrish ·2009-04-02 23:56:24

@tapan...

f'(xy)[ydx/dy+x]=0

implies ydx/dy + x = 0

So, dx/dy = -x/y = -2

@ richa....ques is find dx/dy

UP 0 DOWN 0
Post on FacebookPost anonymously?

21

tapanmast Vora ·2009-04-02 23:57:37

oh k kk..... now i got y RK said f'(xy) â‰ 0

Yeah then it gets much SIMPLER.....

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

vector ·2009-04-03 00:01:48

oh ya thanx

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω