double limit

\hspace{-16}\mathbf{\lim_{x\rightarrow 0}\left[\frac{(1+4x)^{\frac{1}{x}}}{e^4}\right]^{\frac{1}{x}}}

6 Answers

1
Aritra Chakrabarti ·

e-8

1
arahan ·

i am getting ∞ <doesnt exsit>.

262
Aditya Bhutra ·

e-8 is correct.

1
Athenes Analyst ·

Am getting 1 as answer.

We know lim f(x)/g(x) is same as lim f(x)/lim g(x).

Now bring e4/x in denominator and find the limits separately.

You will get lim { e4/x/e4/x} = 1 at the end.

1708
man111 singh ·

Yes answer=e-8

1
Athenes Analyst ·

well I think we have to apply 1infinity type application

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