Doubt on Calculas

A real valued function f is defined on the interval (-1,2).A point x is said to be a fixed point of f if f(x)=x.Suppose that f is a differentiable function such that f(0)>0 and f(1)=1.Show that if f'(1)>1,then f has a fixed point in the interval (0,1).

2 Answers

333
Hardik Sheth ·

draw the graph...its easy..

35
Rohit Chowdhuri ·

Can't figure out the procedure!Please give a suitable solution for it.

  • Hardik Sheth since derivative at 1,greater than 1,slope is greater than the slope of y=x..nw since f(0)greater than 0,u have to cut the line y=x atlest once so that slope of tangent at x=1 is greater than 1

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