FQB-9

Anybody knows how to do this??

is it zero

it must be 0
look mirka
it is

2^{x^n/e^x}-3^{x^n/e^x}/xⁿ

look the denominator is ∞

and e^x>xⁿ when x tends to ∞
and the numerator is 0

so the limit is 0

OK [96]

it is zero becos.

u can see clearly that the denominator goes enormously high when it approaches infinity compard to the numerator.