4
UTTARA
·2009-09-11 07:31:56
@Archana : 20 ) ans B
16 ) A, but i was getting all the options true check out once again
14 th Qs is correct ∩ stands for pie (if u dint understand here)
1
archana anand
·2009-09-11 07:53:53
for 16 option A is neccesarily and sufficiently true......and u cant get c to b true
106
Asish Mahapatra
·2009-09-11 23:02:18
19) f(x) = x3 + 3x2 + 4x + bsinx + c cosx for all x ε R is a one - one function ,
then the greatest value of b2 + c2 is
If it is one-one,
f'(x) = 3x2+6x+4+bcosx-csinx
will have same sign.
Now min. value of 3x2+6x+4 = (4.4.3-36)/4.3 = 1
So, for f'(x) to be +ve always,
min value of bcosx-csinx = -1
this is when b2+c2 = 1
24
eureka123
·2009-09-12 03:04:11
20
Without graph
y={1/x} is continuous and differentiable for all x ε(√2.√3)
=>dy/dx=-1/x2 which is less than zero for all x>0
=> Monotonically decreasing
y={x2} is alos continuous and differentiable in region (√2.√3)
dy/dx=2x which is greater than zero for all x>0
=> Monotonically increasing
Since these 2 curves are monotonically inc .and dec. respectively
so they must intersect only once in the region