g(2012) .....

\hspace{-16}$If $\bf{f(1)=1}$ and $\bf{f(x+5) > f(x) +5 f(x+1) < f(x) + 1}$\\\\ and $\bf{g(x)=f(x)-x+1}$.Then $\bf{g(2012)}$ is

1 Answers

262

Aditya Bhutra ·2012-04-08 10:33:30

f(x) + 5f(x+1) <f(x)+1

f(x+1) < 1/5

but f(1)=1

how is it possible?

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