1It's only an increasing function.
f'(x) = 1 + cos(x)
which depends on cos(x) it's max is 2 and min is 0.
thus , the condition that f(x1) =< f(x2) is satisied.
not f(x1) < f(x2) , for all x1 < x2
is f(x)=x+sinx a strictly increasing or only increasing function
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5 Answers
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62This is a strictly increasing function.
Not just an increasing function.
What lord has explained is partly true.
Actually the points where f'(x)=0 are points of inflection
1good question karan...
It is strictly increasing.
f'(x)>=0 for all x
but f(x)=0 at some points does not make it only increasing
actually f''(x) values need to be checked. this value can be used to confirm what i am saying.
1If targetiit started on 2nd oct 2008 , then how cum this post is of 4th July