integration

∫[sinx + [2x/pi]] dx from pi/4 to pi/2

7 Answers

262
Aditya Bhutra ·

Ans. 0

since in the given interval, 0<(2x/pi)<1 hence [2x/pi]=0
and [sinx]=0

1
Debosmit Majumder ·

i think it shud be a constant

262
Aditya Bhutra ·

@debosmit - this is definite integral.

1
AVISIKTA UPADHYAY ·

could u please check again??? coz the answer is not 0. i myself got 0 as the answer but in the answer key, the answer given is not 0...

ps: could nishant sir please confirm???????

1
satyajit maurya ·

what is ∫0dx =???? is it 0 or a constant?

1
rishabh ·

@avisikta answer is zero and in the key also zero is given.
@satya zero.

1
AVISIKTA UPADHYAY ·

@rishab, my answer key has d wrong answer given in it...:o anyway, i am happy i have given the correct answer.

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