Integration

Q1)∫0pi/4 sin x+cos x/9+16sin 2x

Q2)∫0 pi/2 sin2x tan-1(sinx)dx

4 Answers

1357
Manish Shankar ·

for second
put sinx=t and proceed by byparts

341
Hari Shankar ·

For 1, put sin x - cos x = t. So dt = cos x + sin x

t2 = 1 - sin 2x, so replace sin 2x by 1 - t2

1
Honey Arora ·

cn't 2nd ques be done using properties of integrals anyway?

1357
Manish Shankar ·

I cudn't think of any properties for second one

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