1correct i think,,,,
pls explain it,,,,
1,limit (x-:0) is abbreviated as L0
L0f(x) = l , which is real, then
a) L0f(x2) = l2
b) L0f(xl) = 1
c) L0f(2x) = 2l
d) L0f(-x) = l
2,If La f(x) and Lag(x) exist finitely then an incorrect statement among the following
a) Lafg exist finitely
b) La(kf + hg) exist finitely
c) La(f2 + g2) exist finitely
d) La fg exist finitely
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11 Answers
71For first take the function f(x) = sin x x
For second I agree with Aditya.
71There is no restriction for the f(x) here. So these may be the answers.
1There is 0 or 1 correct answer for both the questions,,,,,,,,,,,,
Anyone pls give a complete solution,,,,,,
11) let f(-x) = g(x)
then when x-> 0+ for f(x) then it'll tend to 0- for g(x)
and when x->0- for f(x) it'll tend to 0+ for g(x)
ultimately i mean to say that LHL for f(x) = RHL for g(x) and RHL for f(x) = LHL for g(x) . [only when x->0]
hence (d)