1PEHLA SUM... ANSWER IS "ONE" OR 1.
SUM NO. 35 ALSO IS ANSWER IS ONE OR 1
NOW PLZ RESPOND TO DIS :)
62pehla sum is correct powerplan
the 2nd is 100 i think
pls check ur answer!
12.) (n+1)10+(n+2)10+..........+(n+100)10
limn->∞ --------------------------------------------------------------------------------
n10 +1010
(10C0n10+10C2n9...)+(10C0n1020 +...) +... 100 terms
= limn->∞ --------------------------------------------------------------------------------
n10 +1010
100X10C0 + 0
= limn->∞ --------------------------------------------------------------------------------
1+0
= 100
131st one, for aneesh... :
n2+1 / n+1 - an
= n2-1+2 / n+1 - an
= n-1 + 2/n+1 - an
lim(n→∞) [(1-a)n - 1 + (2/n)/1+(1/n)]
lim(n→∞) [(1-a)n] - 1 + 0
for d above limit to be finite, coefficient of n must be =0 => a=1
[1]
1first is..
n2(1-a2) -an +1-a
-------------------------------
(n+1)
dividing numerator and dinominator we have n left only in numerator as n(1-a2)
so for limit to exist (1-a2)=0
or a=±1
