11lt x→ what u havent mentioned it
1sry...i've edited the ques. now...
1
mkagenius
·2009-01-27 05:08:28
can u use some more brackets so that i can get the actual ques...
11
Subash
·2009-01-27 05:12:06
plz check ur question
cant the numerator be written as 9+..e1/x
11
Subash
·2009-01-27 05:18:30
whi toh????
what was that if it is hindi plz translate
1
pinky
·2009-01-27 21:05:23
edited once again.....now itz perfect...
1357find the limits for 0+ and 0-
this might help
11
rkrish
·2009-01-27 22:59:09
You r rite manish bhaiyya...thnx...is the answer -2 ??
1
mkagenius
·2009-01-28 02:27:22
just for formality :
LEFT HAND LIMIT(0-):
(e1/x=0)
=>(λ+1)/1=2;
=>λ=1;
RIGHT HAND LIMIT(0+):
(divide num. and deno. by e1/x)
=>8/(1-k)=2;
=>k=-3;
so,.λ+k=1-3=-2;
62good question pinky.
good solution makagenius.
rkrish good work :)
