1708\hspace{-16}\mathbf{\int \frac{x^2}{(a+bx)^2}dx}$\\\\\\ $\mathbf{=\frac{1}{b^2}.\int\frac{(bx)^2}{(a+bx)^2}dx}$\\\\\\ Put $\mathbf{a+bx=t\Leftrightarrow dx=\frac{1}{b}dt}$\\\\\\ $\mathbf{=\frac{1}{b^3}.\int\frac{(t-a)}{t^2}dt=\frac{1}{b^3}\int\frac{1}{t}dt-\frac{a}{b^3}\int\frac{1}{t^2}dt}$\\\\\\ $\mathbf{=\frac{1}{b^3}\ln \mid t\mid +\frac{a}{b^3}.\frac{1}{t}+C}$\\\\\\ So $\mathbf{\int \frac{x^2}{(a+bx)^2}dx=\frac{1}{b^3}\ln \mid a+bx\mid +\frac{a}{b^3}.\frac{1}{a+bx}+C}$
