passage - solve this -3

Let polynomials Pn(x) n=0,1,2,3 ...... , be defined by P0(x)=1

P_{n}(x) = \frac{1}{n!}\frac{d^{n}}{dx^{n}}[x^{n}(1-x)^{n}] , n\geq 1

Answer the following Q's

1)
The \int_{0}^{1}{P_{n}(x)}x^{k}dx , 0\leq k<n is equla to

a) (n-1)/(k+1)
b) k/(1+n)
c) 0
d) k/ (n+1)(k+1)

2)Let Q(x) be a polynomial of degree n , for which \int_{0}^{1}{Q(x)x^{m}}dx=0
holds for all integers 0\leq m<n

Let c be a constant such that Q(x) -c Pn(x) is of degree (n-1)

then the integral \int_{0}^{1}{(Q(x)-cP_{n}(x))^{2}}dx

is equal to
A) (1+c2)/(n+1)
B) c2/(n+1)
C)0
D)(Pn-1)2

3)Let Q(x) be a polynomail of degree 10 such that \int_{0}^{1}{Q(x)x^{k}}dx = 0 for all integers 0\leq k<9

If Q(0) = 1 , then integral \int_{0}^{1}{(Q(x))^{2}}dx

is equal to
A) 1/21
B)3/21
C)2/7
D)3/7

6 Answers

1
Samarth Kashyap ·

1. c
2. b

am i right??????

1
voldy ·

the first one is right . second is wrong .

and method post karo .
did u arrive at it using this ?
\int_{a}^{b}{f(x)}dx = \int_{a}^{b}{f(a+b-x)}dx

only asking baad me kya karna hai ??? mughe thoda problem ho rahahai soln post karo na poora if possible

21
tapanmast Vora ·

DA CAN U INSERT brackets in defining Pn(x) pata nahi chal raha wat is inside the nth derivative and wats inside..

1
voldy ·

edited dude .

1
voldy ·

ok now ??

11
Subash ·

im getting something like a series for that nth derivative thing

Your Answer

Close [X]