da pblm is
25n+1/4
{ 2x+3}
let f(X)=∫ e dx , where {x}denotes da fractional part ...da qn is easy but i dunno wer i went wrong
3
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UP 0 DOWN 0 0 3
3 Answers
6225n+1/4
let f(X)=∫ e{ 2x+3}
3
the period of the function inside the integral is 1/2
for every 1/2 increase in x the power will start to repeat
also, { 2x+3} = {2x}
so this is basically
2(25n-3). integral from 0 to 0.5 of the given expression + 1. integral from 0 to .25 of the given expression. :)
62yup i too felt that there was some issue.. but solved it with what i felt the best guess.
