PLZ SHOW HOW TO SOLVE.. FULLY SOLVE DA PROB ;(

RANGE OF 16-x C 2x-1 + 20-3x C 4x-5 is
(a) [728 , 1474]
(b) {728 , 1474}
(c) {0,728}
(d) none

5 Answers

62
Lokesh Verma ·

what i can see on this one is that

x<=6, x>1

So that this becomes kind of simple?

what i can also see is that

(16-x)=(20-3x) + 2x+4

(2x-1) = (4x-5) + 2x+4

Though this does not help me on the first look.. does it help u?

62
Lokesh Verma ·

btw from the options that you have given it seems to me that the correct answer will be (B)

Dont know why..just gut feeling. (because d is generally not the correct answer)

The range set has a maximum cardinality of 6

So it cant be a)
also, c) is not possible because 0 is an option there!

62
Lokesh Verma ·

x=2 => 14C3+14C3
x=3 => 13C5+11C7

it wont be defined for x>3 either..

so it will be a 2 set... !!!

62
Lokesh Verma ·

yaar the solution was an anticlimax.. i had thought that this wud have something interesting as the solution :D

33
Abhishek Priyam ·

Why this was in calculus...[3]

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