Question No. 2

1 Answers

62
Lokesh Verma ·

The given expression is equal to

(2x-a)2-2a+2

The first term has to be greater than or equal to zero...

It is zero at x=a/2

if a/2 lies between 0 to 2 then the minimum value will be 2-2a=3 ie a=-1/2 which means a/2 does not lie in the interval 0 to 2...

Hence there is no value of x in the given interval

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