simple doubt

Consider the polynomial f(x) = ax2+bx+c.
If f(0) = 0 and f(2) = 2, find the minimum value of \int_{0}^{2}{\left|f'(x) \right|}dx equals??

i get 2a+b=1 (simple), but how to get the value of -b/2a??

3 Answers

1
the_myth ·

well one thing that can straight of be said is determinant > 0

so try graphing the quadratic and

answer has to be in terms of a or b

given data is insufficient in my opinion

62
Lokesh Verma ·

f(0)=0 means that c=0
f(2)=2 means that 4a+2b=2 so 2a+b=1

Now f'(x)=2ax+b=2ax+1-2a=2a(x-1)+1
f'(x)=0 at x=1-1/2a

when we are integrating from 0 to 2 we have to break the limits from 0 to 1-1/2a and then from 1-1/2a to 2

and then find the integral...

Can you finish the rest off?

1
Euclid ·

wow....y cant i think like that!!!! thanx bhaiya...

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