Simple ques on integration

find dy/dx at x=e, y=e2x/logx
a) (e-1)e2e/e
b) o
c) 1
d) (e2-1)e2e/e
plz gv itz soln also
itz a ques from some test here bt i cldn't solve it,so plz help.....................
srry itz derivatives actually...........:)

7 Answers

1
°ღ•๓яυΠ·

r u shoore of d options m gettin an xtra 2 in d answer sumwer

1
moon ·

ys these r the only options

1
°ღ•๓яυΠ·

itz simple bt mah ansewr is nt matchin
logx (y)=e^2x
dy/dx(logx)+1/x(dy/dx)=2e^2x

nw wen x=e y=e^2e substitue 4 it u'll get d ansewr

1
moon ·

u r doing it wrong
thr is mistake in ur 2nd step
logx (y)=e^2x
=>dy/dx(logx)+(1/x)y=2e^2x

1
moon ·

anyways thx,.........nd nw u'll also get the right ans

21
tapanmast Vora ·

wats da ans???

is it a??????//

11
Subash ·

im getting e2e/e(2e-1)

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