1
skygirl
·2009-04-21 07:37:06
chcek f'(x) just before and aftre the point ..
1
skygirl
·2009-04-21 07:37:32
also check f''(x) ... for change of concavity..
11
Mani Pal Singh
·2009-04-21 07:41:22
If a function has a breakpoint at a certain point in the domain, then should we say that the function is increasing or decreasing at that point ????????
Origin of the doubt :-
Is (x+ 1/x) increasing at x=0 ???
L- = -∞
L+ = +∞
Mr Bhavesh
at x=0 the fuction is not defined
so it will be idiotic to talk about x=0
we know x=0 will be the asymptote of thefunction
but ur question have to be modified to make some sense
1
betrayed.... always
·2009-04-21 07:42:53
@ x=0
f' = 1-(1/x2 ) = ∞
f'' also ∞
Ab kya????
1
betrayed.... always
·2009-04-21 07:45:02
Yaar not only dis but also step function is breakfunction at integers
so. is that increasing @integers????
11
Mani Pal Singh
·2009-04-21 07:53:42
mere bhai
at x=0 jab function hi defined nahin hai to uss pe behas karne ka kya faida???
now look at its graph and decide urself
is ur question apt?
1
betrayed.... always
·2009-04-21 08:08:37
The MEGAORIGIN of the Doubt:-
The function x+1/x is non-increasing in the interval[-1,1]
IS dis TRUE or FALSE ????
Mere BADE BHAI plz help now ! :-(
11
Mani Pal Singh
·2009-04-21 08:15:01
i think i have given the graph now ( hopefully correct)
u can see clearly that it is increasing 4m (-1.0)
and decreasing 4m (0,1)