TMH doubt

page 25.18- Example 37,
They hav clearly mentioned a>b;
But all the options are having√b-a. How is that possible??

12 Answers

1
°ღ•๓яυΠ·

post d q
(tmh aieee or tmh iit :P)

39
Dr.House ·

areh yaar, there are many mistakes. we in class picked nearly 150 mistakes in whole year.

39
Dr.House ·

main iit ki baath kar rahatha

1
sriraghav ·

it is for iit...

1
°ღ•๓яυΠ·

post d q

39
Dr.House ·

ek min rukh abhi daalta hoon

1
sriraghav ·

And in page 25.16 exampple 30, I took b2 outside and substituted x = a/b * sinθ, and i got √a2 - b2x2 / (a2b) But answer given is entirely diff. though my method is different , Can anyone of u try check whether mine is correct... Q. is ∫ dx/(a2-b2x2)3/2

39
Dr.House ·

\int \frac{tanx}{\sqrt{a+btan^{2}x}} \left(a>b \right)

39
Dr.House ·

use banao integrations

1
sriraghav ·

mathie... I did in the alternate soln . way(without luking at it),
and i substituted t=√b-a*cos x, in the denominator , after converting all the terms in den. to cos x

1
sriraghav ·

For ∫ dx / (1 + t2)2,
i subs. t= sec x., i am gettin an (2-x2) in the denominator of √x2-1 in the final answer of Qs. 29 page-25.16,
i thought the trig. substi is easier, pls check it.

1
sriraghav ·

For ∫ dx / (1 + t2)2,
i subs. t= sec x., i am gettin an (2-x2) in the denominator of √x2-1 in the final answer of Qs. 29 page-25.16,
i thought the trig. substi is easier, pls check it.

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