9use
tanx = cotx - 2cot2x
ull find succesive terms getting cancelled
ull end up with
cotx/2n/2n - cotx = 1 - cotx
Lim ( n → infinity) { (1/2) tan x/2  + (1/22) tan x/22 + (1/23) tan x/23 .............+(1/2n)tan x/2n) }
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6 Answers
9
1tanx = cotx - 2cot2x
ull find succesive terms getting cancelled
so at last u get
cotx/2n/2n -cot2x
1-cot2x.......
i think its rite....may hav done sum stupid mistakes