urgent

∫(sin8x - cos8x)/(1-2sin2xcos2x)

3 Answers

1
kamalendu ghosh ·

sin^8x-cos^8x=(sin^4x+cos^4x)(sin^2x-cos^2x)
=(1-2sin2xcos2x)(sin^2x-cos^2x)

nw, I think u cn do it..

1
kamalendu ghosh ·

got it boy??? or shud I elaborate??

1
big looser ......... ·

thanks

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