CHEMISTRY

If 1021 molecules are removed from 200 mg of CO2 then the number of moles of CO2 left is

2.88 x 10-3
1.66 x 10-3
4.54 x 10-3
1.66 x 10-2

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Correct Answer
a
please show me the calculation.

1 Answers

156
Rajiv Agarwal ·

44 gm of CO2 contains 6.023 x 1023 molecules
200 mg of CO2 contains = (200x10-3/44) x 6.023 x 1023 molecules

Now, from this number, subtract 1021

This should give you the answer.

Solve and let us know :)

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