269let us consider that the price of each-
burger= Rs.x
pizza= Rs.y and
coke= Rs.z..
Then cost of-
3 burgers= Rs.3x
2 pizzas = Rs.2y
5 cokes = Rs.5z
Now, according to the question, our first equation will be-
3x+2y+5z=565(1)
now, similarly...by the same concept, our second equation will be-
4x+4y+2z=310.....(2)
so,we got our 2 equations as-
3x+2y+5z=565
4x+4y+2z=310
we know that, to solve a equation in three variables...we at least need 3 equations to find out the values.....since there are only two equations...we need to figure out values in a bit different way.....
so, we will multiply equation (1) by 2.to get
6x+4y+10z=1130...(3)
now, we will add eqtn.(3)and(2)...
6x+4y+10z=1130
4x+4y+2z=310
10x+8y+12z=1440
now,dividing both sides by 2...we get
5x+4y+6z=720
that is wat u need....cost of 5 burgers, 4 pizzas and 6 cokes.... so, ur answer is..RS.720..