Exam 2

value of 'a' is 1...an d value of 'b' is -2......

f(x)=ax⁴+2x-3x⁴+bx-4
by factor theorem,we have
→x+2=0
→x=-2
therefore,
f(-2)→a(-2)⁴+2(-2)-3(-2)²+b(-2)-4=0
→16a-4-12-2b-4=0
→16a-20-2b=0
→16a-2b=20
→8a-b=10.........(1)
now,
→x-2=0
→x=2
therefore,
f(2)→a(2)⁴+2(2)-3(2)²+b(2)-4=0
→16a+4-12+2b-4=0
→16a+2b=12
→8a+b=16............(2)
so,you got 2 equations...now solve them......