If n is a positive integer such that n/810 Â = 0d25d25 where d is a single digit in decimal base. Find 'n'...
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2 Answers
206n/810 = 0d25d25??
Does not make sense........i think it will be 0.d25d25
Astha Gupta don't know....u may be ri8....then..wat will be the answer...???Upvote·0· Reply ·2013-08-07 11:11:19
206Since 0.d25d25 is a rational number so
take
x = 0.d25d25.....
Then, 1000x = d25.d25.......
1000x - x = d25.d25.....- 0.d25d25......
→999x = d25
→x = d25/999
Now our equation is n/810 = 0.d25d25....
n = d25 * 810/999
n = d25 * 30/37
Since 'd' is a single digit, assume values from 1 to 9.
Since n is a proper integer, see for which value of d, (d25 * 30) is perfectly divisible by 37.
Then, you can find both d and n.