AA A>0
+ BB B>0
CDC
All A,B,C are digits. Find D
A.4
B.3
C.2
D.1
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2 Answers
29well this is a good one..
Case I
both A and B < 5.
but it can be true as we r getting a three digit number..
so Case II
A + B > 10
so we have AA+BB = CDC..
ie A+B = 1C.
now tens place
D = A + B +1 ..and at hundred's place we have C..so C = 1..so D = 2
the summation is 121..and the numbers will be 77 and 44..