Truck.
A truck and a car are moving with the same K.E. on a straight line road. If their engines are turned off at the same time, which one of them will stop at a lesser distance?

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9 Answers
Same KE.
KE=0.5m^{2}∞v^{2}
So, if KE is constant for both the vehicles,
constant=0.5mv^{2}
let constant KE be k
So,
→k=0.5mv^{2}
→k0.5=mv^{2}
→k0.51m=v^{2}
→v^{2}∞1m
→m∞1v^{2}
We assume mass of truck>car
So, more the mass lesser the velocity.
So, truck has lesser velocity.
So, truck will stop faster.
Also, weight of truck is more. Assuming we have same quality tyres for both the vehicles (i.e. coefficient of kinetic friction is same for both), friction=kN will be more for the truck. So more friction. This again adds to the retardation. So, truck stops faster.
Thanx...
 Sayantan Hazra The logic shown is perfectly correct........only that u must show s_truck < s_car............
Good work!! :)Upvote·0· Reply ·20130606 12:19:58
since you have to compute which one stops at a lesser distance, compare the distances moved by them after engine is switched off......
Hint: F_{fric} = uN
→ ma = uN.........(if a be the retardation)
Then the retardations are being same as...
ma=uN
N=mg (most of the time)
ma=umg
a=ug
If u is same for both, both will have equal retardation.
I hope my first part was correct where I showed m is inversely proportional to v^{2}.
And, v^{2}=u^{2}2aS
Here, v=0
For truck u is lesser.
u^{2}=2aS
→lesser the velocity, lesser the distance as retardation is the same...
Very Good !! :)....another green for you!!
 Sayan Sinha Truly! A tricky thing: retardations are being same... By and large, a gr8 sum...
if the truck and the car is opposed by same backward force which will stop first?
Calculate it yourself......and then see.. :)
Hint: Same breaking force, or backward force means
F_{truck} = F_{car}
or, m_{1}a_{1} = m_{2}a_{2}
Can we not say that assuming that the truck has more mass than the car, thus it will possess more inertia and thus it will stop at a farther distance than the car???.....if not then please tell why and please explain me the sum since i couldnt follow it...