Sem9

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A person moves a certain dist. in a certain time. 1/3 of dist. is covered in 2/3 of time with speed V₁ and 2/3 of distance is covered in 1/3 of time with speed V₂ then V₁/V₂=?
a)1/2
b)1/4
c)1/9
d)2/9

#Physics #Class VII-X Physics

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269

Astha Gupta ·2013-06-22 00:14:35

the answer is ....option b.....

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Sayantan Hazra Show the method also.......it is convenient for the person asking the question.....
Upvote·0· Reply ·2013-06-27 05:39:56
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269

Astha Gupta ·2013-06-27 10:10:56

sorry for troubling you.....

let the total distance be 'd' and total time be 't'
1st case
according to the question,
distance covered is=d3
time taken=2t3
therefore, V₁= d3 / 2t3 = d3x32t [since,v=dt]
=d2t
2nd case
distance covered=2d3
time taken=t3
therfore, V₂=2d3/t3 =2d3x3t
=2dt
therefore, V₁V₂ =d2t/2dt = d2txt2d=14
that's your answer.....[option B]

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