1well in q 16
force is acting in x direction...due to hinge...so ans shud be c
10 Answers
11in q 15...
assume we join p n q by a rod...
so it is a rod rotating wit w....so it will look like a rod moving wit speed wa/2
so potential difference will be (Bwa^2)/2....
direction of w is not mentioned ...so cannot decide statement 2
[7]
better go wit c tats wat my sir said[3]
106@rickde: the central axis is O naa??
So even if we consider a rod to be der in PQ
shouldnt emf be ∫Bwxdx limits from a to 2a ?
16.. y force due to hinge?? it is due to string tension naa?? which is internal force so, momentum is conserved?
1in q 14...
\omega _{AwrtG}=-\omega \hat{k}
\omega _{BwrtG}=-\omega \hat{k}
so
\omega _{BwrtA}=-\omega \hat{k}+\omega \hat{k}=0
ans d
1@ asish the pulley is attached to wall....it will exert some force innit???
the situation is like this...the mass m1 suddenly applies a jerk to the pully..trying to tear it away n the hinge holds it back.....
1while integrating...did u take care that the direction of velocity is different everytime...did u take its component correctly???
10614. given B
@rickde: the situation can be imagined like this, when the string becomes taut, it exerts an impulsive force on m1 and m2 which consequently makes them move at same speed.
This same tension only creates the reaction of hinge (which doesnt affect teh m1, m2, string system at all) .. The reaction depends only on the impulsive tension developed