2624) if angular velocity remains constant ,
t = (2m-1m)/1m/s =1s
θ = ωt = π/2
hence m rotates by an angle 900 .
let θ =0 at t=0
initial vel = (-1)i +(2ω)j
final vel = (-ω)i + (-1)j
change in vel = (1-ω)i + (-1-2ω)j
impulse = m*Δv
7 Answers
262
21Initially when battery is connected,charge accumulates and energy is stored.
Einitial=1/2(C/3)V2
Charge on each capacitor=CV/3
Now when, the inductor is connected,energy oscillates.Assume the capacitors behave like a single capacitor,with capacitance C/3.Now when the switch is switched on,the capacitance of the system reduces to C/2.Let at this instant charge on each capacitor be Q.
We can also note that as soon as the 2 plates of the middle capacitor are connected,it immediately discharges,and energy is lost.(ie 1/3rd of original energy).
By energy conservation:
2/3Einitial=Efinal
2/3*(1/2(C/3)V2)=1/2*Q2/(C/2)
Hence,
Q=CV/3 [after so much calc. Q is same as initial,proof of the fact that when battery is removed Q remains same]
Therefore amplitude of charge oscillation on the capacitors=CV/3
w=√2/LC [net capacitance of system is C/2]
1is the answer given by swaraj correct?
'cos im getting a different one
71I don't have the answer, but what is given by Swaraj is in the options!