a conducting wire moves normally in a magnetic field with a uniform speed V..what will be its speed after it gets out of the field??
30Its speed should be V only as when the conductor is not conducting any current, at any point in time, the movement of the electrons and protons within the wire is arbitrary and average velocity of the particles is zero. Hence, no magnetic force acts on it. Wire passes through the field without deflection.
49Ashish: I din attempt this question because of one term that occurred to me. The term is "eddy current".
What do u feel now?
30Eddy currents (also called Foucault currents) are currents induced in conductors, when a conductor is exposed to a changing magnetic field due to relative motion of the field source and conductor; or due to variations of the field with time. This can cause a circulating flow of electrons, or a current, within the body of the conductor. These circulating eddies of current have inductance and thus induce magnetic fields. These fields can cause repulsive, attractive propulsion and drag effects. The stronger the applied magnetic field, or the greater the electrical conductivity of the conductor, or the faster the field changes, then the greater the currents that are developed and the greater the fields produced.
Source : Wikipedia
Then, in that case, how will we find the interaction of the conductor with the external field?
