Current Electricity-10

JEE Advanced 2015 Discussion Forum › Electricity and magnetism questions › Current Electricity-10

#Physics #Electricity and magnetism

UP 0 DOWN 0 0 4
Post on FacebookPost anonymously?

4 Answers

229

Dwijaraj Paul Chowdhury ·2013-06-29 19:06:16

For each bulb....power =v²/r
:. r= v²/p
= 220*220/100 =484
Equivalent resistance(R) =4r/3
:.POWER = V²/R
=( 220*220*3) / (4*484)
= 75 watts

UP 2 DOWN 0
Post on FacebookPost anonymously?

229

Dwijaraj Paul Chowdhury ·2013-06-26 02:36:59

A)__75watts

UP 0 DOWN 3
Akash Anand Good Work
Upvote·0· Reply ·2013-06-26 03:56:35
Akash Anand Try to post a crisp solution after 1/2 day so that other people can take a hint.
Upvote·0· Reply ·2013-06-26 22:50:14
Akash Anand Try to post a crisp solution after 1/2 day so that other people can take a hint.
Upvote·0· Reply ·2013-06-26 22:50:14
Post on FacebookPost anonymously?

1

Subhradeep Patra ·2013-06-26 03:23:37

D> 400/3 watts?

UP 0 DOWN 1
Akash Anand Wrong..try again.
Upvote·0· Reply ·2013-06-26 03:56:22
Post on FacebookPost anonymously?

535

Aditya Agarwal ·2013-06-29 13:59:47

sir the solution?

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω