1in @ashish's diagram lets mark the surfaces as 1,2,3,4 ..now my doubt is that how do we say/assume the field due to which surface is in which direction?!!!
plz can someone explain me how the charges are distributed in conductors placed side by side .
i know i am going wrong somewhere but yet not able to understand .
sample question
3 conductors- A B C
+Q 0 -2Q
Find final charge distribution.
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23 Answers
49u seem not to appreciate the mess u just made in your copy after solving a problem! [3]
I used to appreciate those things like hand writing, the diagrams etc for at least 1 minute after the sum was solved!
This revealed many of the hidden secrets like this to me! :P
Try appreciating the mess you created after each battle! You wud suddenly become a pro in the topic! :D
1
30The good thing is that you need not worry whether it is positive or negative. Just assume postive/negative and stick to it till the end. Your answer will carry a negative sign if you assumed something wrong. Just make sure to report the answer after correcting that incorrect assumption . [1]
1i don't get how can we say that at 'p' the field due to which plate is in which direction...
as we are not given the magnitudes...how do we know that Q - q is positive or negative...??
30Thats what he meant. Sometimes its just all about appreciating the "mess" of our handwriting. :D
71@Appreciating the mess :
" Whenever I appreciate my hand writing and all, I began to loose everything out of my mind.. Even my handwriting becomes unreadable to me "
How to tackle this.. Now I don't have time to improve my hand writing either!! :)
49Why get into competition? :P
Appreciate all the mess u made after u made it! ;)
30Bhaiya I do this but then the thought that comes to my mind (and it always does!) "okay nothing to get so inflated. You're not the only one who did it!" And then I move on. But I can tell you I do come back at times and look with pleasure at THE MESS!
49once it went till 2 hours! :P
I had attempted that sum for 3 days! [3]
21@subhomoy da:
:P ''I used to appreciate those things like hand writing, the diagrams etc for at least 1 minute after the sum was solved!''
i also do, sometimes 5-10 mins :P
49http://www.targetiit.com/iit-jee-forum/posts/capacitor-19509.html
30Wow. This seems to be a nice generalisation. Never thought of it! [1]
491/2(sum total of charge in the system) lies in the outer surface of the external plates(ie: A & C)
this is the result of the fact that field inside a conductor is necessarily 0 in conditions of electrostatics! [1]
262thnx guys.... thats why i wasnt able to solve even a question from h.c.verma
30Where does this come from "1/2(sum total of charge in the system) lies in the outer surface of the external plates(ie: A & C)"?
1For check : 1/2(sum total of charge in the system) lies in the outer surface of the external plates(ie: A & C).And the inner one behaves as a parallel plate capacitor(ie: +q &-q).And total charge in any plate is constant. so the ans must be(-Q/2,3Q/2 ;-3Q/2,+3Q/2 ;-3Q/2,-Q/2)
30You're making a mistake. The field at the point P in your diagram is not zero. Take a point inside any of the two conducting plates and find the field there. Over there, the field can be equated to zero. Like in the above example, lets take a point Q inside the first plate having charge +Q.
Net field (+ve towards right) = k(Q-q) - Kq - Kq + Kq
hence,
Q - q - q = 0
Giving, q = Q2
262i have already done these steps but i am going wrong somewhere while finding field at p and equating to zero. plz help me in that portion
for eg. lets take a small question-
A B
+Q 0
find the final charge distribution
i have checked h.c.verma but can not understand the soln. they have also taken the siqn of the charge while finding the field
262i have done that but am not being able to get the correct ans.